P1591. 阶乘数码

考点

  • 高精度

题解

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#include <bits/stdc++.h>

using namespace std;

const int LEN = 25050;

class BigInt
{
public:
int len_;
int arr_[LEN];
int &operator[](int idx)
{
return arr_[idx];
}
BigInt(int x = 0)
{
memset(arr_, 0, sizeof(arr_));
for (len_ = 1; x; ++len_)
{
arr_[len_] = x % 10;
x /= 10;
}
--len_;
}
void flatten(int len)
{
len_ = len;
for (int i = 1; i <= len_; ++i)
{
if (arr_[i] >= 10)
{
arr_[i + 1] += arr_[i] / 10;
arr_[i] %= 10;
}
}
while (!arr_[len_])
--len_;
}
void print()
{
for (int i = max(1, len_); i >= 1; --i)
{
cout << arr_[i];
}
}
};

BigInt operator*(BigInt a, int b)
{
BigInt c;
int len = a.len_;
for (int i = 1; i <= len; ++i)
{
c[i] += a[i] * b;
}
c.flatten(len + 11);
return c;
}

int cnt(BigInt a, int x)
{
int ans = 0;
for (int i = 1; i <= a.len_; ++i)
{
if (a[i] == x)
++ans;
}
return ans;
}

int main()
{
int t, n, x;
cin >> t;
while (t--)
{
cin >> n >> x;
BigInt a(1);
for (int i = 1; i <= n; ++i)
{
a = a * i;
}
cout << cnt(a, x) << endl;
}
return 0;
}

思路

高精乘低精的模板题,没有坑点